Practical case: Zener Diode as a Voltage Regulator

Zener Diode as a Voltage Regulator prototype (Maker Style)

Level: Medium. Design and verify a voltage stabilizer circuit using a Zener diode under load variations.

Objective and use case

In this session, you will build a shunt voltage regulator using a Zener diode and a series limiting resistor to maintain a fixed 5.1 V output from a 9 V source.

  • Why it is useful:
    • Provides a stable reference voltage for Analog-to-Digital Converters (ADCs).
    • Protects sensitive downstream components (like microcontrollers) from over-voltage spikes.
    • Regulates voltage for low-power circuits without the complexity of an IC regulator.
  • Expected outcome:
    • The output voltage (VOUT) remains clamped at approximately 5.1 V despite the input being 9 V.
    • Connecting a moderate load (470 Ω) decreases Zener current but maintains VOUT at 5.1 V.
    • If the load resistance becomes too low, the regulation fails, and VOUT drops below 5.1 V.
  • Target audience: Electronics students, Level: Medium.

Materials

  • V1: 9 V DC voltage source, function: main power supply.
  • R1: 220 Ω resistor, function: series current limiting (RS).
  • D1: 1N4733 A Zener diode (5.1 V, 1 W), function: shunt voltage regulator.
  • R2: 470 Ω resistor, function: load simulation (RL).
  • M1: Multimeter (Voltmeter mode), function: measure output voltage.
  • M2: Multimeter (Ammeter mode), function: measure Zener current (IZ).

Wiring guide

Construct the circuit using the following connections and SPICE node names (VIN, VOUT, 0):

  • V1 (9 V Supply): Connect Positive terminal to node VIN and Negative terminal to node 0 (GND).
  • R1 (Series Resistor): Connect one terminal to VIN and the other terminal to node VOUT.
  • D1 (Zener Diode): Connect the Cathode (striped end) to node VOUT and the Anode to node 0.
  • R2 (Load Resistor): Connect one terminal to VOUT and the other terminal to node 0.
  • Measurements:
    • To measure VOUT: Connect the Voltmeter Positive probe to VOUT and Negative probe to 0.
    • To measure IZ: Break the connection between D1 Cathode and VOUT, and insert the Ammeter in series (Positive to VOUT, Negative to D1 Cathode).

Conceptual block diagram

Conceptual block diagram — Zener Voltage Regulator
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ SOURCE ]                 [ LIMITING ]                     [ REGULATION, LOAD & MEASUREMENT ]

                                                                           (Branch 1: Regulation)
                                                                 +---> [ Ammeter M2 ] --> [ D1: Zener 5.1 V ] --> GND
                                                                 |     (Measure Iz)       (Shunt Regulator)
                                                                 |
    [ V1: 9 V DC ] --(VIN)--> [ R1: 220 Ohm ] --(Node VOUT)--> ---+
    (Main Power)             (Series Resistor)                   |         (Branch 2: Load)
                                                                 +---> [ R2: 470 Ohm ] ------------------------> GND
                                                                 |     (Load Simulation)
                                                                 |
                                                                 |         (Branch 3: Monitoring)
                                                                 +---> [ Voltmeter M1 ] -----------------------> GND
                                                                       (Measure Vout)
Schematic (ASCII)

Electrical diagram

Electrical diagram for case: Zener diode as a voltage regulator
Generated from the validated SPICE netlist for this case.

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Measurements and tests

Follow these steps to validate the regulator design:

  1. Open Circuit Test (No Load):

    • Temporarily disconnect R2.
    • Measure voltage at VOUT. It should read approximately 5.1 V.
    • Calculate the current flowing through the Zener: IZ = (VIN – VZ) / R1. Expect ≈ 17.7 mA.
  2. Load Regulation Test:

    • Reconnect R2 (470 Ω) between VOUT and 0.
    • Measure VOUT again. It should remain stable at 5.1 V.
    • Observe the Zener current. It should decrease because some current is now diverted through the load RL.
    • Expected Load Current (IL): 5.1 V / 470 Ω ≈ 10.8 mA.
    • Remaining Zener Current: ≈ 17.7 mA – 10.8 mA = 6.9 mA. Since IZ > 0, regulation holds.
  3. Overload Test (Simulation):

    • Replace R2 with a 100 Ω resistor (if available) or simulate a short.
    • Measure VOUT. The voltage will drop significantly below 5.1 V because the load demands more current than R1 can supply while maintaining the Zener breakdown voltage.

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* Practical case: Zener Diode as a Voltage Regulator

* --- Power Supply ---
* V1: 9 V DC voltage source (Main Supply)
V1 VIN 0 DC 9

* --- Components ---
* R1: 220 Ohm Resistor (Series Current Limiting)
* Wiring: Connect one terminal to VIN and the other to VOUT
R1 VIN VOUT 220

* R2: 470 Ohm Resistor (Load Simulation)
* Wiring: Connect one terminal to VOUT and the other to 0 (GND)
R2 VOUT 0 470

* M1: Multimeter (Voltmeter mode)
* Wiring: Positive probe to VOUT, Negative probe to 0
* Implementation: High impedance resistor to simulate voltmeter load
R_M1_Voltmeter VOUT 0 10Meg

* ... (truncated in public view) ...

Copy this content into a .cir file and run with ngspice.

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* Practical case: Zener Diode as a Voltage Regulator

* --- Power Supply ---
* V1: 9 V DC voltage source (Main Supply)
V1 VIN 0 DC 9

* --- Components ---
* R1: 220 Ohm Resistor (Series Current Limiting)
* Wiring: Connect one terminal to VIN and the other to VOUT
R1 VIN VOUT 220

* R2: 470 Ohm Resistor (Load Simulation)
* Wiring: Connect one terminal to VOUT and the other to 0 (GND)
R2 VOUT 0 470

* M1: Multimeter (Voltmeter mode)
* Wiring: Positive probe to VOUT, Negative probe to 0
* Implementation: High impedance resistor to simulate voltmeter load
R_M1_Voltmeter VOUT 0 10Meg

* M2: Multimeter (Ammeter mode)
* Wiring: Inserted in series between VOUT and D1 Cathode
* Positive to VOUT, Negative to D1 Cathode (Node: VZ_CATHODE)
* Implementation: 0V DC source to measure current
V_M2_Ammeter VOUT VZ_CATHODE DC 0

* D1: 1N4733A Zener Diode (5.1 V, 1 W)
* Wiring: Cathode to VZ_CATHODE, Anode to 0
* Note: Cathode is connected to VOUT through the Ammeter
D1 0 VZ_CATHODE D1N4733A

* --- Models ---
* Model for 1N4733A Zener Diode
* BV=5.1V (Breakdown Voltage), IBV=49mA (Test Current)
.model D1N4733A D(IS=2.5n RS=1 N=1.2 BV=5.1 IBV=49m)

* --- Analysis ---
* Transient analysis (1ms simulation time)
.tran 1u 1ms

* --- Output Directives ---
* Print voltages and Zener current (Iz)
.print tran V(VIN) V(VOUT) I(V_M2_Ammeter)

* Operating Point for initial check
.op

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (1008 rows)
Index   time            v(vin)          v(vout)         v_m2_ammeter#br
0	0.000000e+00	9.000000e+00	5.047821e+00	7.223902e-03
1	1.000000e-08	9.000000e+00	5.047805e+00	7.224007e-03
2	2.000000e-08	9.000000e+00	5.047805e+00	7.224007e-03
3	4.000000e-08	9.000000e+00	5.047805e+00	7.224007e-03
4	8.000000e-08	9.000000e+00	5.047805e+00	7.224007e-03
5	1.600000e-07	9.000000e+00	5.047805e+00	7.224007e-03
6	3.200000e-07	9.000000e+00	5.047805e+00	7.224007e-03
7	6.400000e-07	9.000000e+00	5.047805e+00	7.224007e-03
8	1.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
9	2.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
10	3.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
11	4.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
12	5.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
13	6.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
14	7.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
15	8.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
16	9.280000e-06	9.000000e+00	5.047805e+00	7.224007e-03
17	1.028000e-05	9.000000e+00	5.047805e+00	7.224007e-03
18	1.128000e-05	9.000000e+00	5.047805e+00	7.224007e-03
19	1.228000e-05	9.000000e+00	5.047805e+00	7.224007e-03
20	1.328000e-05	9.000000e+00	5.047805e+00	7.224007e-03
21	1.428000e-05	9.000000e+00	5.047805e+00	7.224007e-03
22	1.528000e-05	9.000000e+00	5.047805e+00	7.224007e-03
23	1.628000e-05	9.000000e+00	5.047805e+00	7.224007e-03
... (984 more rows) ...

Common mistakes and how to avoid them

  1. Reversing the Zener Diode:
    • Error: Connecting the Anode to VOUT and Cathode to GND.
    • Result: The circuit behaves like a standard diode, clamping the output to ≈ 0.7 V instead of 5.1 V.
    • Solution: Ensure the striped end (Cathode) is connected to the positive potential (VOUT).
  2. Using a Series Resistor (R1) with too high resistance:
    • Error: Using 10 kΩ instead of 220 Ω for R1.
    • Result: When the load (R2) is connected, the voltage drops immediately; the Zener turns off because there isn’t enough current to keep it in breakdown.
    • Solution: Calculate R1 such that enough current flows to satisfy both the load and the minimum Zener bias current (IZK).
  3. Exceeding Zener Power Rating:
    • Error: Removing the load while using a very small R1.
    • Result: All current flows through the Zener, causing it to overheat and potentially burn out.
    • Solution: Ensure PZ = VZ × Izmax is less than the diode’s power rating (e.g., 1 W).

Troubleshooting

  • Symptom: Output voltage is equal to Input voltage (9 V).
    • Cause: Zener diode is open (broken) or not connected.
    • Fix: Check connections to D1 or replace the diode.
  • Symptom: Output voltage is ≈ 0.7 V.
    • Cause: Zener diode is connected in forward bias (backwards).
    • Fix: Reverse the diode orientation.
  • Symptom: Output is 5.1 V without load, but drops to 3 V (or lower) when load is attached.
    • Cause: The load resistance is too low (drawing too much current) or R1 is too high.
    • Fix: Increase the load resistance or recalculate R1 for higher current delivery (watching power limits).

Possible improvements and extensions

  1. Series Pass Transistor: Add an NPN transistor (like a 2N2222) with the Zener controlling the base. This creates a Series Voltage Regulator capable of handling much higher load currents.
  2. Filtering: Add a capacitor (e.g., 10 µF) in parallel with the Zener diode to filter out noise and improve the stability of the voltage reference.

More Practical Cases on Prometeo.blog

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Quick Quiz

Question 1: What is the primary function of the Zener diode in the described circuit?




Question 2: What is the expected output voltage (VOUT) of this circuit when functioning correctly?




Question 3: Which component is responsible for limiting the current flowing through the Zener diode?




Question 4: How must the Zener diode be biased in this circuit to regulate voltage?




Question 5: What happens to the Zener current when a moderate load (470 Ω) is connected in parallel?




Question 6: Under what condition does the voltage regulation of this circuit fail?




Question 7: Why is this circuit useful for Analog-to-Digital Converters (ADCs)?




Question 8: Which specific Zener diode model is specified in the materials list?




Question 9: What is the primary purpose of the 9 V DC source (V1) in this setup?




Question 10: Besides providing a reference voltage, what is another key use case for this circuit?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

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Practical case: Full-wave bridge rectifier

Full-wave bridge rectifier prototype (Maker Style)

Level: Medium – Analyze a Graetz bridge to convert AC to pulsating DC and measure total voltage drop.

Objective and use case

In this practical case, you will build a standard Graetz bridge circuit using four diodes and an AC voltage source to supply a resistive load. This circuit converts an alternating current input (where voltage polarity changes) into a pulsating direct current output (where voltage polarity remains positive).

Why it is useful:
* Power Supplies: It is the fundamental first stage in converting AC mains power to DC for charging laptops, phones, and powering appliances.
* Motor Control: Used in DC motor drives to run motors from an AC supply.
* Polarity Protection: Ensures that a device works correctly regardless of how the input power wires are connected.
* High Efficiency: Utilizes both the positive and negative half-cycles of the AC input, unlike a half-wave rectifier.

Expected outcome:
* Input Signal: A sinusoidal waveform (e.g., 12 V RMS / ~17 V Peak) at 60Hz.
* Output Signal: A series of positive «mounds» (pulsating DC) at 120Hz (double the input frequency).
* Voltage Drop: The peak output voltage will be approximately 1.4 V lower than the peak input voltage due to the forward voltage drop of two diodes in series (2 × 0.7 V).
* Current Flow: Current flows through the load resistor in the same direction during both AC half-cycles.

Target audience and level: Electronics students and hobbyists familiar with basic diode biasing.

Materials

  • V1: AC Voltage Source (Amplitude: 17 V [12Vrms], Frequency: 60Hz), function: Input supply
  • D1: 1N4007 Diode, function: Rectifier (Bridge arm 1)
  • D2: 1N4007 Diode, function: Rectifier (Bridge arm 2)
  • D3: 1N4007 Diode, function: Rectifier (Bridge arm 3)
  • D4: 1N4007 Diode, function: Rectifier (Bridge arm 4)
  • R1: 1 kΩ resistor, function: Output Load

Wiring guide

This guide uses specific node names to represent the connections. Ensure the AC source is floating relative to the DC ground to simulate the isolation provided by a transformer.

  • V1 (Positive terminal) connects to node AC1.
  • V1 (Negative terminal) connects to node AC2.
  • D1 (Anode) connects to node AC1.
  • D1 (Cathode) connects to node VOUT.
  • D2 (Anode) connects to node AC2.
  • D2 (Cathode) connects to node VOUT.
  • D3 (Anode) connects to node 0 (GND).
  • D3 (Cathode) connects to node AC1.
  • D4 (Anode) connects to node 0 (GND).
  • D4 (Cathode) connects to node AC2.
  • R1 connects between node VOUT and node 0 (GND).

Conceptual block diagram

Conceptual block diagram — LM7812 Full-Wave Bridge Rectifier
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ INPUT SOURCE ]               [ PROCESSING / LOGIC ]               [ OUTPUT LOAD ]

[ AC Source V1 ]
(17 V Amp / 60Hz)
       |
       +----(Node AC1)----->+-----------------------------+
                            |    FULL-WAVE BRIDGE         |
                            |                             |
                            |  [ Diodes D1 & D2 ]         |
                            |  (Direct Positive Peaks)    |--(Node VOUT)--> [ Resistor R1 ]
                            |                             |                 (1 kOhm)
                            |                             |                     |
       +----(Node AC2)----->|  [ Diodes D3 & D4 ]         |                     |
       |                    |  (Direct Negative Peaks)    |                     v
       |                    |  (Create Return Path)       |                    GND
(Source Return)             |                             |
                            +-----------------------------+
                                          |
                                          v
                                     (Node 0/GND)
Schematic (ASCII)

Electrical diagram

Electrical diagram for case: Full-wave bridge rectifier
Generated from the validated SPICE netlist for this case.

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Measurements and tests

Perform the following steps to validate the circuit operation using an oscilloscope or a multimeter:

  1. Input Verification: Connect channel 1 of the oscilloscope across AC1 and AC2. Verify a full sine wave with a frequency of 60Hz.
  2. Output Visualization: Connect channel 2 of the oscilloscope across R1 (Probe on VOUT, Clip on 0). Observe that the negative portions of the sine wave have been «flipped» up, creating a continuous chain of positive pulses.
  3. Frequency Measurement: Measure the frequency of the signal at VOUT. It should be exactly 120Hz (double the input frequency).
  4. Voltage Drop Analysis: Measure the peak voltage of the Input (Vpeakin) and the peak voltage of the Output (Vpeakout).
    • Vpeakout should be approximately Vpeakin – 1.4 V. This accounts for the 0.7 V drop across D1 and 0.7 V drop across D4 (during one cycle) or D2 and D3 (during the other).

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* Title: Practical case: Full-wave bridge rectifier

* --- Component Instantiation ---

* V1: AC Voltage Source (Amplitude: 17 V, Frequency: 60Hz)
* Wiring: V1 (Positive) -> AC1, V1 (Negative) -> AC2
* Note: Source is floating relative to ground (Node 0), connected only to the bridge.
V1 AC1 AC2 SIN(0 17 60)

* D1: 1N4007 Diode (Bridge arm 1)
* Wiring: Anode -> AC1, Cathode -> VOUT
D1 AC1 VOUT 1N4007

* D2: 1N4007 Diode (Bridge arm 2)
* Wiring: Anode -> AC2, Cathode -> VOUT
D2 AC2 VOUT 1N4007

* D3: 1N4007 Diode (Bridge arm 3)
* Wiring: Anode -> 0 (GND), Cathode -> AC1
D3 0 AC1 1N4007
* ... (truncated in public view) ...

Copy this content into a .cir file and run with ngspice.

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* Title: Practical case: Full-wave bridge rectifier

* --- Component Instantiation ---

* V1: AC Voltage Source (Amplitude: 17 V, Frequency: 60Hz)
* Wiring: V1 (Positive) -> AC1, V1 (Negative) -> AC2
* Note: Source is floating relative to ground (Node 0), connected only to the bridge.
V1 AC1 AC2 SIN(0 17 60)

* D1: 1N4007 Diode (Bridge arm 1)
* Wiring: Anode -> AC1, Cathode -> VOUT
D1 AC1 VOUT 1N4007

* D2: 1N4007 Diode (Bridge arm 2)
* Wiring: Anode -> AC2, Cathode -> VOUT
D2 AC2 VOUT 1N4007

* D3: 1N4007 Diode (Bridge arm 3)
* Wiring: Anode -> 0 (GND), Cathode -> AC1
D3 0 AC1 1N4007

* D4: 1N4007 Diode (Bridge arm 4)
* Wiring: Anode -> 0 (GND), Cathode -> AC2
D4 0 AC2 1N4007

* R1: 1 kΩ Resistor (Output Load)
* Wiring: VOUT -> 0 (GND)
R1 VOUT 0 1k

* --- Models ---
* Standard model for 1N4007 Rectifier Diode
.model 1N4007 D (IS=7.03n RS=0.034 N=1.81 BV=1000 IBV=0.5u CJO=10p TT=0.1u)

* --- Analysis Commands ---
* Transient analysis: 60Hz period is ~16.6ms.
* Simulating 50ms to capture approximately 3 full cycles.
.tran 50u 50m

* --- Output Directives ---
* Print voltages at AC inputs (relative to GND) and the rectified Output
.print tran V(AC1) V(AC2) V(VOUT)

* Calculate DC operating point
.op

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (1016 rows)
Index   time            v(ac1)          v(ac2)          v(vout)
0	0.000000e+00	3.036573e-18	3.036573e-18	-7.53268e-22
1	5.000000e-07	1.602212e-03	-1.60221e-03	-9.54567e-15
2	1.000000e-06	3.204481e-03	-3.20437e-03	1.126318e-07
3	2.000000e-06	6.409036e-03	-6.40866e-03	3.747988e-07
4	4.000000e-06	1.281816e-02	-1.28172e-02	9.375665e-07
5	8.000000e-06	2.563689e-02	-2.56338e-02	3.056599e-06
6	1.600000e-05	5.127600e-02	-5.12650e-02	1.103556e-05
7	3.200000e-05	1.025657e-01	-1.02513e-01	5.319168e-05
8	6.400000e-05	2.053399e-01	-2.04787e-01	5.532611e-04
9	1.140000e-04	3.725509e-01	-3.57833e-01	1.471794e-02
10	1.640000e-04	5.903791e-01	-4.60003e-01	1.303764e-01
11	2.140000e-04	8.628382e-01	-5.07168e-01	3.556700e-01
12	2.640000e-04	1.155738e+00	-5.33407e-01	6.223310e-01
13	3.140000e-04	1.456815e+00	-5.50867e-01	9.059481e-01
14	3.640000e-04	1.761378e+00	-5.64128e-01	1.197250e+00
15	4.140000e-04	2.068103e+00	-5.74401e-01	1.493702e+00
16	4.640000e-04	2.375673e+00	-5.82891e-01	1.792782e+00
17	5.140000e-04	2.683430e+00	-5.90142e-01	2.093289e+00
18	5.640000e-04	2.990978e+00	-5.96439e-01	2.394538e+00
19	6.140000e-04	3.297988e+00	-6.02000e-01	2.695989e+00
20	6.640000e-04	3.604206e+00	-6.06966e-01	2.997240e+00
21	7.140000e-04	3.909408e+00	-6.11453e-01	3.297955e+00
22	7.640000e-04	4.213406e+00	-6.15537e-01	3.597869e+00
23	8.140000e-04	4.516026e+00	-6.19284e-01	3.896742e+00
... (992 more rows) ...

Common mistakes and how to avoid them

  1. Ground Loops (Scope): Connecting the oscilloscope ground clip to AC1 or AC2 while the circuit is mains-referenced can cause a short circuit. Solution: Only connect the scope ground to the common circuit ground (0) at the load, or use a differential probe for the input.
  2. Diode Orientation: Inserting a diode backward in the bridge. Solution: Ensure that two diodes point towards the positive DC output node (VOUT) and two diodes point away from the ground node (0).
  3. Ignoring Power Ratings: Using a resistor with low wattage for R1. Solution: Calculate power P = V^2 / R. For 17 V peak, P ≈ 0.3W. Use a 0.5W resistor or greater.

Troubleshooting

  • Symptom: The output looks like a half-wave rectifier (gaps between pulses).
    • Cause: One of the diodes is open (disconnected or blown).
    • Fix: Check continuity of all four diodes; replace the faulty one.
  • Symptom: Zero output voltage.
    • Cause: Short circuit in the load or open circuit in the source/wiring.
    • Fix: Check connections at AC1 and AC2; ensure R1 is not shorted.
  • Symptom: Input fuse blows or source current is excessive.
    • Cause: One or more diodes are shorted, or a diode is installed in reverse (creating a direct path from AC to Ground).
    • Fix: Test diodes for shorts using the diode check mode on a multimeter.

Possible improvements and extensions

  1. Filtering: Add a capacitor (e.g., 470 µF) in parallel with R1 to fill in the gaps between pulses, creating a smooth DC voltage (Ripple reduction).
  2. Regulation: Connect a voltage regulator (like an LM7812 or a Zener diode circuit) after the filter capacitor to produce a constant, stable DC voltage regardless of input fluctuations.

More Practical Cases on Prometeo.blog

Find this product and/or books on this topic on Amazon

Go to Amazon

As an Amazon Associate, I earn from qualifying purchases. If you buy through this link, you help keep this project running.

Quick Quiz

Question 1: What is the primary function of a Graetz bridge circuit?




Question 2: How many diodes are typically used to build a standard Graetz bridge?




Question 3: Why is the Graetz bridge considered more efficient than a half-wave rectifier?




Question 4: If the input AC frequency is 60Hz, what is the frequency of the pulsating DC output in a Graetz bridge?




Question 5: What is the approximate total voltage drop expected at the peak output compared to the peak input?




Question 6: Why does the voltage drop occur in this circuit?




Question 7: Which component serves as the rectifying element in the described circuit?




Question 8: What happens to the direction of current flow through the load resistor during the negative half-cycle of the AC input?




Question 9: If the input source provides 12 V RMS, what is the approximate peak voltage amplitude mentioned in the text?




Question 10: Besides power supplies, what is another use case mentioned for the Graetz bridge?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

Follow me:


Practical case: Voltage limiter with series diodes

Voltage limiter with series diodes prototype (Maker Style)

Level: Basic – Build a circuit to clamp load voltage using diode forward drops.

Objective and use case

In this practical case, you will build a passive voltage limiter (clipper) circuit. By placing multiple silicon diodes in series parallel to the load, you will create a hard «ceiling» for the output voltage, preventing it from exceeding the sum of the forward voltage drops of the diodes.

  • Input protection: Prevents high voltage spikes from damaging sensitive microcontroller inputs (ADCs).
  • Simple regulation: Provides a crude but effective constant voltage reference without a Zener diode.
  • Signal conditioning: Used in audio circuits to create distortion or «fuzz» effects by clipping signal peaks.
  • Logical reference: Can be used to establish specific logic threshold levels in analog computing.

Expected outcome:
* When Input Voltage < ~2.1 V: The output voltage follows the input (minus minor resistive losses).
* When Input Voltage > ~2.1 V: The output voltage clamps and remains stable at approximately 2.1 V.
* The current through the diodes increases significantly once the threshold is reached.
* Target audience: Students and hobbyists learning about diode I-V characteristics.

Materials

  • V1: 0 V to 9 V Variable DC Power Supply, function: Input signal source.
  • R1: 1 kΩ resistor, function: Current limiting for the diodes and source protection.
  • R2: 10 kΩ resistor, function: Load resistor (simulating a downstream circuit).
  • D1: 1N4148 Silicon Diode, function: First voltage drop element (~0.7 V).
  • D2: 1N4148 Silicon Diode, function: Second voltage drop element (~0.7 V).
  • D3: 1N4148 Silicon Diode, function: Third voltage drop element (~0.7 V).

Wiring guide

Construct the circuit following these connections. The node names (e.g., VIN, VOUT, 0) refer to specific electrical points in the circuit. Node 0 represents the Ground (GND).

  • V1 (Source): Connect the positive terminal to node VIN and the negative terminal to node 0.
  • R1 (Limiter): Connect one pin to node VIN and the other pin to node VOUT.
  • R2 (Load): Connect one pin to node VOUT and the other pin to node 0.
  • D1: Connect the Anode to node VOUT and the Cathode to intermediate node N1.
  • D2: Connect the Anode to intermediate node N1 and the Cathode to intermediate node N2.
  • D3: Connect the Anode to intermediate node N2 and the Cathode to node 0.

Note: This creates a chain where D1, D2, and D3 are in series with each other, and that entire string is in parallel with R2.

Conceptual block diagram

Conceptual block diagram — Series Diode Limiter
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ INPUT SOURCE ]              [ SERIES LIMITER ]                  [ OUTPUT NODE & BRANCHES ]

                                                                 /------> [ R2: 10 kΩ Load ] ---------> GND (0)
                                                                 |
[ V1: 0-9 V Variable ] --(VIN)--> [ R1: 1 kΩ Resistor ] --(VOUT)-->+
                                                                 |
                                                                 |        [ VOLTAGE CLAMP CHAIN ]
                                                                 |
                                                                 \------> [ D1: 1N4148 ] --(N1)-->+
                                                                                                  |
                                                                          [ D2: 1N4148 ] <--------+
                                                                          |
                                                                          +--(N2)--> [ D3: 1N4148 ] --> GND (0)
Schematic (ASCII)

Electrical diagram

Electrical diagram for practical case: Voltage limiter with series diodes
Generated from the validated SPICE netlist for this case.

🔒 This electrical diagram is premium. With the 7-day pass or the monthly membership you can unlock the complete didactic material and the print-ready PDF pack.🔓 See premium access plans

Measurements and tests

Follow these steps to validate the limiting behavior.

  1. Low Voltage Test (Below Threshold):

    • Set V1 to 1.0 V.
    • Measure the voltage at VOUT relative to GND.
    • Expected Result: VOUT should be approximately 0.9 V – 1.0 V (diodes are off/high impedance; R1 and R2 form a voltage divider).
  2. Transition Test (Near Threshold):

    • Set V1 to 2.5 V.
    • Measure the voltage at VOUT.
    • Expected Result: VOUT begins to lag behind VIN. Diodes start conducting. VOUT will likely be around 1.8 V to 2.0 V.
  3. Clamping Test (Above Threshold):

    • Set V1 to 9.0 V.
    • Measure the voltage at VOUT.
    • Expected Result: VOUT should be clamped at approximately 2.1 V to 2.2 V (3 diodes × ~0.7 V each). It will NOT reach 9 V.
  4. Transfer Curve Sweep:

    • Slowly increase V1 from 0 V to 9 V while monitoring VOUT.
    • Observe that VOUT rises linearly initially, then «knees» over and flattens out around 2.1 V.

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* Practical case: Voltage limiter with series diodes

* --- Power Supply / Input Signal ---
* V1: 0 V to 9 V Variable DC Power Supply
* Modeled as a linear ramp (PWL) from 0V to 9V over 10ms
* This allows the transient analysis to show the voltage limiting characteristic.
V1 VIN 0 PWL(0 0 10m 9)

* --- Resistors ---
* R1: 1 kΩ resistor (Current limiting)
* Connects VIN to VOUT
R1 VIN VOUT 1k

* R2: 10 kΩ resistor (Load)
* Connects VOUT to Ground (0)
R2 VOUT 0 10k

* --- Diodes ---
* Chain of 3 diodes in series, connected in parallel with the load (R2).
* This clamps VOUT to approximately 3 * 0.7V = 2.1V.
* ... (truncated in public view) ...

Copy this content into a .cir file and run with ngspice.

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* Practical case: Voltage limiter with series diodes

* --- Power Supply / Input Signal ---
* V1: 0 V to 9 V Variable DC Power Supply
* Modeled as a linear ramp (PWL) from 0V to 9V over 10ms
* This allows the transient analysis to show the voltage limiting characteristic.
V1 VIN 0 PWL(0 0 10m 9)

* --- Resistors ---
* R1: 1 kΩ resistor (Current limiting)
* Connects VIN to VOUT
R1 VIN VOUT 1k

* R2: 10 kΩ resistor (Load)
* Connects VOUT to Ground (0)
R2 VOUT 0 10k

* --- Diodes ---
* Chain of 3 diodes in series, connected in parallel with the load (R2).
* This clamps VOUT to approximately 3 * 0.7V = 2.1V.

* D1: 1N4148 Silicon Diode
* Anode -> VOUT, Cathode -> N1
D1 VOUT N1 1N4148

* D2: 1N4148 Silicon Diode
* Anode -> N1, Cathode -> N2
D2 N1 N2 1N4148

* D3: 1N4148 Silicon Diode
* Anode -> N2, Cathode -> Ground (0)
D3 N2 0 1N4148

* --- Models ---
* Standard model for 1N4148 small signal diode
.model 1N4148 D (IS=2.682n N=1.836 RS=0.5664 BV=100 IBV=20n CJO=4p TT=11.54n)

* --- Simulation Directives ---
* Perform a transient analysis for 10ms (matching the input ramp duration)
* Step size 10us
.tran 10u 10m

* Calculate DC operating point
.op

* Output data for plotting/logging
.print tran V(VIN) V(VOUT) V(N1) V(N2)

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (2016 rows)
Index   time            v(vin)          v(vout)         v(n1)
0	0.000000e+00	0.000000e+00	-9.87864e-23	2.810146e-18
1	1.000000e-07	9.000000e-05	8.083682e-05	5.389121e-05
2	2.000000e-07	1.800000e-04	1.626418e-04	1.084279e-04
3	4.000000e-07	3.600000e-04	3.262751e-04	2.175167e-04
4	8.000000e-07	7.200000e-04	6.535424e-04	4.356949e-04
5	1.600000e-06	1.440000e-03	1.308076e-03	8.720508e-04
6	3.200000e-06	2.880000e-03	2.617144e-03	1.744763e-03
7	6.400000e-06	5.760000e-03	5.235279e-03	3.490186e-03
8	1.280000e-05	1.152000e-02	1.047155e-02	6.981032e-03
9	2.280000e-05	2.052000e-02	1.865321e-02	1.243547e-02
10	3.280000e-05	2.952000e-02	2.683486e-02	1.788991e-02
11	4.280000e-05	3.852000e-02	3.501650e-02	2.334434e-02
12	5.280000e-05	4.752000e-02	4.319814e-02	2.879876e-02
13	6.280000e-05	5.652000e-02	5.137976e-02	3.425317e-02
14	7.280000e-05	6.552000e-02	5.956137e-02	3.970758e-02
15	8.280000e-05	7.452000e-02	6.774297e-02	4.516198e-02
16	9.280000e-05	8.352000e-02	7.592455e-02	5.061637e-02
17	1.028000e-04	9.252000e-02	8.410612e-02	5.607075e-02
18	1.128000e-04	1.015200e-01	9.228768e-02	6.152512e-02
19	1.228000e-04	1.105200e-01	1.004692e-01	6.697948e-02
20	1.328000e-04	1.195200e-01	1.086507e-01	7.243383e-02
21	1.428000e-04	1.285200e-01	1.168323e-01	7.788817e-02
22	1.528000e-04	1.375200e-01	1.250137e-01	8.334250e-02
23	1.628000e-04	1.465200e-01	1.331952e-01	8.879681e-02
... (1992 more rows) ...

Common mistakes and how to avoid them

  1. Reversing diode polarity: If diodes are connected Cathode-to-Anode (facing up towards positive), they will not conduct in forward bias. Solution: Ensure the band (Cathode) of D3 connects to Ground, and the arrows point from VOUT to Ground.
  2. Omitting R1: Connecting the source directly to the diode string without R1 causes a short circuit when V1 > 2.1 V, likely destroying the diodes. Solution: Always include a series resistor (R1) to drop the excess voltage.
  3. Using a low resistance load (R2): If R2 is very small (e.g., 100 Ω), it will dominate the circuit and reduce VOUT below the clamping threshold purely by voltage division. Solution: Ensure the load R2 is significantly larger than R1 (at least 10x larger) for sharp clamping action.

Troubleshooting

  • Symptom: VOUT equals VIN for the entire 0-9 V range.
    • Cause: The diode path is open.
    • Fix: Check for loose connections in the D1-D2-D3 string or a backwards diode blocking current.
  • Symptom: VOUT stays near 0 V even when VIN is increased.
    • Cause: Diodes are shorted or one diode is reversed and connected in parallel with the supply incorrectly (though R1 usually protects this).
    • Fix: Check diode orientation. If a diode is reversed parallel to the load, it clamps at -0.7 V (essentially 0 V in this setup).
  • Symptom: The clamping voltage is ~0.7 V or ~1.4 V instead of ~2.1 V.
    • Cause: One or two diodes are shorted or bypassed.
    • Fix: Verify that exactly three healthy diodes are in the series string.

Possible improvements and extensions

  1. Adjustable Clamp: Replace the fixed D1-D3 string with a Zener diode (e.g., 3.3 V or 5.1 V) to set a specific protection voltage with a single component.
  2. Visual Indication: Replace one of the standard diodes with a red LED. The clamp voltage will rise (LEDs drop ~1.8 V – 2.0 V), and the LED will light up when the input voltage exceeds the limit, acting as an «Overvoltage Warning.»

More Practical Cases on Prometeo.blog

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Quick Quiz

Question 1: What is the primary function of the circuit described in this practical case?




Question 2: How is the voltage 'ceiling' established in this specific circuit design?




Question 3: What happens to the output voltage when the input voltage exceeds approximately 2.1 V?




Question 4: What is the primary purpose of the resistor R1 (1 kΩ) in this circuit?




Question 5: Which component represents the downstream circuit or load in this experiment?




Question 6: What is the approximate forward voltage drop of a single standard silicon diode like the 1N4148?




Question 7: When used for input protection, what specific threat does this circuit mitigate?




Question 8: In the context of audio circuits, what effect does this clipping signal conditioning produce?




Question 9: How does the current flowing through the diodes behave once the voltage threshold is reached?




Question 10: To achieve a clamping threshold of ~2.1 V using silicon diodes (approx. 0.7 V drop each), how many are needed in series?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

Follow me:


Practical case: Reverse polarity protection

Reverse polarity protection prototype (Maker Style)

Level: Basic – Demonstrate how a diode protects a sensitive circuit (like a DC motor) if the battery is connected backwards.

Objective and use case

In this practical case, you will build a safety circuit that allows current to flow to a load (a DC motor) only when the battery is connected with the correct polarity.

  • Prevents damage to components: Essential for protecting polarized components like electrolytic capacitors and microcontrollers from exploding or burning out.
  • Automotive applications: Used in car electronics (ECUs, radios) to prevent damage if the car battery is installed incorrectly.
  • Consumer electronics: Protects toys and handheld devices where users might insert batteries backwards.

Expected outcome:
* Correct Polarity: The motor spins, and the voltage at the load is approximately 0.7 V lower than the battery voltage.
* Reverse Polarity: The motor remains completely off (0 V at the load), ensuring no reverse current damages the device.
* Voltage Drop: Measurement of the characteristic forward voltage drop (~0.6 V to 0.7 V) across the silicon diode.

Target audience: Hobbyists and basic electronics students.

Materials

  • V1: 9 V Battery or DC Power Supply, function: Main energy source.
  • D1: 1N4007 Rectifier Diode, function: Blocks current flow in reverse direction.
  • M1: 9 V DC Hobby Motor, function: The sensitive load being protected.
  • S1: SPST Toggle Switch (Optional), function: Master ON/OFF control.

Wiring guide

This circuit puts the diode in series with the positive rail of the power supply.

  • V1 (Positive Terminal) connects to node BAT_POS.
  • V1 (Negative Terminal) connects to node 0 (GND).
  • S1 (if used) connects between BAT_POS and node SWITCHED_POS. (If not used, connect BAT_POS directly to SWITCHED_POS).
  • D1 (Anode) connects to node SWITCHED_POS.
  • D1 (Cathode) connects to node LOAD_IN. (The striped band on the physical component marks the cathode).
  • M1 (Positive Terminal) connects to node LOAD_IN.
  • M1 (Negative Terminal) connects to node 0 (GND).

Conceptual block diagram

Conceptual block diagram — Reverse Polarity Protection
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ POWER SOURCE ]              [ LOGIC / PROTECTION ]                 [ OUTPUT LOAD ]

+---------------------+       +-----------+        +--------------+       +--------------+
|   9 V Battery (V1)   |       | Switch S1 |        |   Diode D1   |       |   Motor M1   |
|      (Positive)     |------>|  (SPST)   |------->|   (1N4007)   |------>|   (9 V DC)    |-----> [ GND ]
+---------------------+   ^   +-----------+    ^   | Anode->Cath  |   ^   +--------------+
                          |                    |   +--------------+   |
                      (BAT_POS)          (SWITCHED_POS)           (LOAD_IN)
Schematic (ASCII)

Electrical diagram

Electrical diagram for case: Reverse polarity protection
Generated from the validated SPICE netlist for this case.

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Measurements and tests

To validate the protection, perform the following steps using a multimeter:

  1. Forward Bias Test (Normal Operation):

    • Connect V1 correctly (Positive to Anode side).
    • Observe: The motor M1 spins.
    • Measure: Place the red probe on LOAD_IN and the black probe on 0 (GND). Expect a reading of approx. 8.3 V to 8.4 V (9 V input minus the diode drop).
  2. Diode Drop Measurement:

    • With the circuit powered ON, place probes across D1 (Red on SWITCHED_POS, Black on LOAD_IN).
    • Result: You should read approximately 0.6 V to 0.7 V. This confirms the diode is conducting.
  3. Reverse Bias Test (Simulation of Error):

    • Disconnect V1 and reverse the connections (Positive to GND, Negative to the input of the switch/diode).
    • Observe: The motor M1 does not spin. It is completely safe.
    • Measure: Place the red probe on LOAD_IN and the black probe on the battery negative (now at the top). The reading should be 0 V. Current is blocked.

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* TITLE: Practical case: Reverse polarity protection

* --- Bill of Materials & Component Models ---

* V1: 9 V Battery or DC Power Supply
* Function: Main energy source
* Connected between BAT_POS and GND (0)
V1 BAT_POS 0 DC 9

* S1: SPST Toggle Switch
* Function: Master ON/OFF control
* Connected between BAT_POS and SWITCHED_POS
* Modeled as a voltage-controlled switch driven by a stimulus source to simulate user action.
S1 BAT_POS SWITCHED_POS CTRL_NODE 0 SW_MODEL
.model SW_MODEL SW(Vt=2.5 Ron=0.1 Roff=100Meg)

* Stimulus for S1 (User pressing the switch)
* Switch is OPEN (0V) initially, closes (5V) at 100us.
V_S1_ACT CTRL_NODE 0 PULSE(0 5 100u 1u 1u 10m 20m)

* ... (truncated in public view) ...

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* TITLE: Practical case: Reverse polarity protection

* --- Bill of Materials & Component Models ---

* V1: 9 V Battery or DC Power Supply
* Function: Main energy source
* Connected between BAT_POS and GND (0)
V1 BAT_POS 0 DC 9

* S1: SPST Toggle Switch
* Function: Master ON/OFF control
* Connected between BAT_POS and SWITCHED_POS
* Modeled as a voltage-controlled switch driven by a stimulus source to simulate user action.
S1 BAT_POS SWITCHED_POS CTRL_NODE 0 SW_MODEL
.model SW_MODEL SW(Vt=2.5 Ron=0.1 Roff=100Meg)

* Stimulus for S1 (User pressing the switch)
* Switch is OPEN (0V) initially, closes (5V) at 100us.
V_S1_ACT CTRL_NODE 0 PULSE(0 5 100u 1u 1u 10m 20m)

* D1: 1N4007 Rectifier Diode
* Function: Blocks current flow in reverse direction
* Anode -> SWITCHED_POS, Cathode -> LOAD_IN
D1 SWITCHED_POS LOAD_IN D1N4007
* Standard generic model for 1N4007
.model D1N4007 D(IS=7.03n RS=0.034 N=1.8 BV=1000 IBV=5u CJO=10p VJ=0.7 M=0.5 TT=100n)

* M1: 9 V DC Hobby Motor
* Function: The sensitive load being protected
* Connected between LOAD_IN and GND (0)
* Modeled as a Series Resistor (winding resistance) and Inductor
R_M1 LOAD_IN M1_INTERNAL 45
L_M1 M1_INTERNAL 0 5m

* --- Analysis & Output Directives ---

* Transient analysis to observe the switch turning on and voltage drop across diode
.tran 10u 2m

* Print directives for ngspice batch mode
.print tran V(BAT_POS) V(SWITCHED_POS) V(LOAD_IN)

* Operating point analysis
.op

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (233 rows)
Index   time            v(bat_pos)      v(switched_pos) v(load_in)
0	0.000000e+00	9.000000e+00	1.216207e-01	3.995271e-06
1	1.000000e-07	9.000000e+00	1.216207e-01	3.995280e-06
2	2.000000e-07	9.000000e+00	1.216207e-01	3.995265e-06
3	4.000000e-07	9.000000e+00	1.216207e-01	3.995282e-06
4	8.000000e-07	9.000000e+00	1.216207e-01	3.995257e-06
5	1.600000e-06	9.000000e+00	1.216207e-01	3.995290e-06
6	3.200000e-06	9.000000e+00	1.216207e-01	3.995250e-06
7	6.400000e-06	9.000000e+00	1.216207e-01	3.995292e-06
8	1.280000e-05	9.000000e+00	1.216207e-01	3.995249e-06
9	2.280000e-05	9.000000e+00	1.216207e-01	3.995292e-06
10	3.280000e-05	9.000000e+00	1.216207e-01	3.995249e-06
11	4.280000e-05	9.000000e+00	1.216207e-01	3.995292e-06
12	5.280000e-05	9.000000e+00	1.216207e-01	3.995249e-06
13	6.280000e-05	9.000000e+00	1.216207e-01	3.995292e-06
14	7.280000e-05	9.000000e+00	1.216207e-01	3.995249e-06
15	8.280000e-05	9.000000e+00	1.216207e-01	3.995292e-06
16	9.280000e-05	9.000000e+00	1.216207e-01	3.995249e-06
17	1.000000e-04	9.000000e+00	1.216207e-01	3.995292e-06
18	1.001000e-04	9.000000e+00	1.216207e-01	3.995267e-06
19	1.002600e-04	9.000000e+00	1.216207e-01	3.995284e-06
20	1.003075e-04	9.000000e+00	1.216207e-01	3.995227e-06
21	1.003906e-04	9.000000e+00	1.216207e-01	3.995299e-06
22	1.004136e-04	9.000000e+00	1.216207e-01	3.995334e-06
23	1.004539e-04	9.000000e+00	1.216207e-01	3.995198e-06
... (209 more rows) ...

Common mistakes and how to avoid them

  1. Installing the diode backwards: The circuit will not work even with the correct battery polarity. Always ensure the silver band (cathode) points toward the load (M1).
  2. Using a signal diode for high loads: Using a small 1N4148 for a high-current motor may cause the diode to overheat and fail. Use a 1N400x series diode (1 A rating) for motors.
  3. Ignoring voltage drop: Students often forget that the diode «eats» about 0.7 V. If your load requires exactly 9 V, supplying 9 V through a diode might result in under-performance (8.3 V).

Troubleshooting

  • Symptom: Motor runs slower than expected.
    • Cause: The voltage drop across the diode reduces the effective voltage at the motor.
    • Fix: Increase the supply voltage slightly or use a Schottky diode.
  • Symptom: Diode gets very hot.
    • Cause: The motor draws more current than the diode is rated for.
    • Fix: Check the motor’s current draw and replace D1 with a higher amperage diode (e.g., 1N5408 for 3 A).
  • Symptom: Motor works in both battery orientations.
    • Cause: The diode has failed short (internal damage) or is bypassed by a wire.
    • Fix: Test the diode with the «Diode Check» function on a multimeter; replace if it conducts in both directions.

Possible improvements and extensions

  1. Schottky Diode Upgrade: Replace the 1N4007 with a 1N5817 (Schottky). Measure the voltage drop again; it should be lower (~0.3 V), making the circuit more efficient.
  2. Full Bridge Rectifier: Replace the single diode with a bridge rectifier consisting of 4 diodes. This allows the device to work regardless of polarity (auto-correction) rather than just blocking the wrong polarity.

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Quick Quiz

Question 1: What is the primary function of the diode in this circuit?




Question 2: What happens to the DC motor if the battery is connected with reverse polarity in this circuit?




Question 3: Which component is typically identified as 'D1' in this type of circuit?




Question 4: What is the approximate voltage drop expected across the silicon diode when the polarity is correct?




Question 5: Why is this circuit important for components like electrolytic capacitors?




Question 6: If the battery voltage is 9 V and the diode drop is 0.7 V, what is the approximate voltage at the load?




Question 7: How is the diode typically connected in this protection circuit?




Question 8: Which of the following is a listed use case for this circuit?




Question 9: What role does the battery (often labeled V1) play in this circuit?




Question 10: Who is the stated target audience for this practical case?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

Follow me:


Practical case: Simple half-wave rectification

Simple half-wave rectification prototype (Maker Style)

Level: Basic. Visualizing how a diode converts AC to pulsating DC by removing the negative half-cycle.

Objective and use case

You will build a fundamental analog circuit that uses a single semiconductor diode to block the negative portion of an alternating current (AC) signal, passing only the positive portion to a resistive load.

Why it is useful:
* Power conversion: It represents the first stage in converting AC mains power to DC for electronic devices.
* Signal demodulation: Used in AM radios to extract audio signals from radio frequency carriers (envelope detector).
* Polarity protection: Similar logic prevents damage to DC circuits if batteries are inserted backward.

Expected outcome:
* Input Signal: A complete sine wave swinging between positive and negative voltages (e.g., +10 V to -10 V).
* Output Signal: A pulsating waveform showing only the positive «humps» of the sine wave; the voltage sits at 0 V during the negative cycle.
* Voltage Drop: The peak output voltage will be approximately 0.7 V lower than the input peak due to the silicon diode forward voltage drop.
* Frequency: The output frequency remains identical to the input frequency.

Target audience and level: Students and hobbyists learning basic analog components.

Materials

  • V1: 10 V (peak), 60 Hz AC voltage source (sine wave), function: main power input.
  • D1: 1N4007 (or 1N4148), function: rectifier diode.
  • R1: 1 kΩ resistor, function: resistive load.

Wiring guide

This guide defines the connections between components using specific node names (VIN, VOUT, 0).

  • V1 (Source): Connect the positive terminal to node VIN and the negative terminal to node 0 (GND).
  • D1 (Diode): Connect the Anode to node VIN and the Cathode (marked with a stripe) to node VOUT.
  • R1 (Load): Connect one terminal to node VOUT and the other terminal to node 0 (GND).

Conceptual block diagram

Conceptual block diagram — Half-Wave Rectification
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ SOURCE / INPUT ]             [ RECTIFICATION ]               [ LOAD / OUTPUT ]

[ V1: AC Source    ]           +----------------------+           [ R1: Resistor   ]
[ 10 V Peak, 60Hz   ] --(VIN)-->| Anode (A) -> Cathode | --(VOUT)--> [ 1 kΩ         ] --> GND
                               | D1: 1N4007           |
                               +----------------------+
Schematic (ASCII)

Electrical diagram

Electrical diagram for case: Simple half-wave rectification
Generated from the validated SPICE netlist for this case.

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Measurements and tests

To validate the circuit, you will need a dual-channel oscilloscope or a simulation tool.

  1. Setup Probes:
    • Connect Channel A (Yellow) to VIN to monitor the source.
    • Connect Channel B (Blue) to VOUT to monitor the voltage across the resistor.
    • Ensure the ground clips of both probes are connected to node 0 (GND).
  2. Visual Inspection:
    • Observe that VIN is a full sine wave centered at 0 V.
    • Observe that VOUT follows VIN during the positive cycle but stays flat at 0 V during the negative cycle.
  3. Cursor Measurement:
    • Measure the peak voltage of VIN (e.g., 10.0 V).
    • Measure the peak voltage of VOUT. It should be approximately 9.3 V.
    • Calculate the difference (Vin – Vout). This confirms the roughly 0.7 V forward voltage drop of the silicon diode.

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* Practical case: Simple half-wave rectification

* --- Circuit Description ---
* V1 (Source): 10V Peak, 60Hz Sine Wave
* D1 (Diode): 1N4007 Rectifier
* R1 (Load): 1k Ohm Resistor

* --- Components ---

* V1: Main power input
* Connected: Positive -> VIN, Negative -> 0 (GND)
* Syntax: SIN(Voffset Vamp Freq)
V1 VIN 0 SIN(0 10 60)

* D1: Rectifier diode (1N4007)
* Connected: Anode -> VIN, Cathode -> VOUT
D1 VIN VOUT 1N4007

* R1: Resistive load
* Connected: VOUT -> 0 (GND)
* ... (truncated in public view) ...

Copy this content into a .cir file and run with ngspice.

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* Practical case: Simple half-wave rectification

* --- Circuit Description ---
* V1 (Source): 10V Peak, 60Hz Sine Wave
* D1 (Diode): 1N4007 Rectifier
* R1 (Load): 1k Ohm Resistor

* --- Components ---

* V1: Main power input
* Connected: Positive -> VIN, Negative -> 0 (GND)
* Syntax: SIN(Voffset Vamp Freq)
V1 VIN 0 SIN(0 10 60)

* D1: Rectifier diode (1N4007)
* Connected: Anode -> VIN, Cathode -> VOUT
D1 VIN VOUT 1N4007

* R1: Resistive load
* Connected: VOUT -> 0 (GND)
R1 VOUT 0 1k

* --- Models ---
* Standard model for 1N4007 Diode
.model 1N4007 D (IS=7.69n RS=0.042 N=1.45 BV=1000 IBV=5u CJO=14.2p VJ=0.5 M=0.333 TT=4.32u)

* --- Analysis Commands ---
* Transient analysis
* Frequency is 60Hz (Period ~16.67ms).
* Simulate for 50ms to capture approximately 3 full cycles.
.tran 0.1ms 50ms

* Operating Point for initial check
.op

* --- Output Directives ---
* Print input voltage and rectified output voltage
.print tran V(VIN) V(VOUT)

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (515 rows)
Index   time            v(vin)          v(vout)
0	0.000000e+00	0.000000e+00	-2.01593e-21
1	1.000000e-06	3.769911e-03	5.704546e-05
2	2.000000e-06	7.539822e-03	5.927562e-05
3	4.000000e-06	1.507964e-02	6.305993e-05
4	8.000000e-06	3.015924e-02	7.111847e-05
5	1.600000e-05	6.031821e-02	1.021853e-04
6	3.200000e-05	1.206342e-01	3.070797e-04
7	5.378437e-05	2.027484e-01	2.167324e-03
8	7.424258e-05	2.798514e-01	1.250260e-02
9	9.741093e-05	3.671480e-01	4.715921e-02
10	1.262516e-04	4.757778e-01	1.182339e-01
11	1.839330e-04	6.928557e-01	2.983890e-01
12	2.467131e-04	9.287461e-01	5.130162e-01
13	3.467131e-04	1.303359e+00	8.676123e-01
14	4.467131e-04	1.676120e+00	1.226655e+00
15	5.467131e-04	2.046499e+00	1.587509e+00
16	6.467131e-04	2.413969e+00	1.947514e+00
17	7.467131e-04	2.778010e+00	2.305173e+00
18	8.467131e-04	3.138102e+00	2.659882e+00
19	9.467131e-04	3.493735e+00	3.010809e+00
20	1.046713e-03	3.844404e+00	3.357375e+00
21	1.146713e-03	4.189609e+00	3.698904e+00
22	1.246713e-03	4.528861e+00	4.034877e+00
23	1.346713e-03	4.861677e+00	4.364712e+00
... (491 more rows) ...

Common mistakes and how to avoid them

  1. Reversing the diode:
    • Error: The diode is installed with the cathode pointing toward the source.
    • Result: The circuit produces negative voltage pulses instead of positive ones.
    • Solution: Verify the stripe (cathode) points toward the load resistor.
  2. Ignoring power ratings:
    • Error: Using a very small resistor (e.g., 10 Ω) with a standard 1/4W resistor.
    • Result: The resistor overheats and burns.
    • Solution: Calculate power (P = V^2 / R) or use a resistor value like 1 kΩ or higher for demonstration purposes.
  3. Floating Ground:
    • Error: Measuring VOUT without a common ground reference between the source and the oscilloscope.
    • Result: Noisy or floating signals on the screen.
    • Solution: Ensure all grounds (Source, Resistor, Oscilloscope) are tied to node 0.

Troubleshooting

  • Symptom: No output voltage (0 V flatline).
    • Cause: Diode is open (blown) or disconnected.
    • Fix: Check continuity with a multimeter; replace the diode.
  • Symptom: Output is identical to Input (full sine wave).
    • Cause: Diode is shorted internally.
    • Fix: Replace the diode; a shorted diode acts like a wire.
  • Symptom: Output peak is significantly lower than expected (e.g., 5 V drop).
    • Cause: High internal resistance of the source or an incorrect component (e.g., using a Zener diode in reverse breakdown).
    • Fix: Verify the diode part number is a standard rectifier (1N400x series).

Possible improvements and extensions

  1. Filter Capacitor: Connect a capacitor (e.g., 10 µF) in parallel with R1 to observe how the capacitor fills in the gaps between pulses, smoothing the DC output.
  2. Full-Wave Bridge: Replace the single diode with four diodes (bridge configuration) to utilize both the positive and negative halves of the AC cycle, improving efficiency.

More Practical Cases on Prometeo.blog

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Quick Quiz

Question 1: What is the primary function of the semiconductor diode in this circuit?




Question 2: What is the expected shape of the output signal?




Question 3: How does the output frequency compare to the input frequency in this half-wave rectifier?




Question 4: Why is the peak output voltage slightly lower than the input peak voltage?




Question 5: Approximately how much voltage is typically dropped across a standard silicon diode?




Question 6: In a standard schematic for this circuit, which component typically acts as the load?




Question 7: What happens to the voltage at the output during the negative cycle of the input?




Question 8: Which of the following is a practical use case for this type of circuit mentioned in the text?




Question 9: To allow positive current to flow from the source to the load, how should the diode be oriented?




Question 10: If the input signal swings between +10 V and -10 V, what is the approximate peak output voltage?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

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Practical case: Forward and Reverse Diode Biasing

Forward and Reverse Diode Biasing prototype (Maker Style)

Level: Basic. Verify the diode’s behavior as a unidirectional switch by measuring current and voltage in both polarities.

Objective and use case

In this experiment, you will build a simple series circuit consisting of a DC voltage source, a current-limiting resistor, and a silicon diode. You will measure the voltage drop across the diode and the current flowing through the circuit to confirm how the component blocks or conducts electricity based on its orientation.

  • Reverse polarity protection: Prevents damage to sensitive electronics if a battery is inserted backwards.
  • AC to DC Rectification: Converts alternating current into direct current in power supplies.
  • Signal clipping: Limits voltage levels to protect downstream components in communication circuits.
  • Logic implementation: Forms the basis of DTL (Diode-Transistor Logic) gates.

Expected outcome:
* Forward Bias: The diode conducts current; voltage across the diode (VD) stays near 0.7 V.
* Reverse Bias: The diode blocks current (I ≈ 0 A); voltage across the diode equals the supply voltage (Vsupply).
* Unidirectional flow: Confirmation that electrons only flow effectively in one direction (Anode to Cathode).

Target audience: Students and beginners in basic analog electronics.

Materials

  • V1: 9 V DC supply (battery or bench power supply).
  • R1: 1 kΩ resistor, function: current limiting and current sensing.
  • D1: 1N4148 silicon diode (or 1N4007), function: Device Under Test (DUT).
  • Multimeter: Digital multimeter, function: measuring DC voltage and DC current.

Wiring guide

This guide describes the Forward Bias configuration. The nodes are defined as VCC (9 V), N1 (junction), and 0 (GND).

  • V1: Connect the positive terminal to node VCC and the negative terminal to node 0.
  • R1: Connect one leg to node VCC and the other leg to node N1.
  • D1: Connect the Anode (side without the stripe) to node N1 and the Cathode (side with the stripe) to node 0.

Conceptual block diagram

Conceptual block diagram — Forward Biased Diode Circuit
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ POWER SOURCE ]               [ CIRCUIT PROCESSING ]                [ RETURN PATH ]

[ V1: 9 V DC Supply ] --(+9 V)--> [ R1: 1 kΩ Resistor ] --(Node N1)--> [ D1: 1N4148 Diode ] --(0 V)--> [ GND ]
                                (Current Limiting)    (Measurement)    (Anode -> Cathode)
                                                                        (Forward Biased)
Schematic (ASCII)

Electrical diagram

Electrical diagram for case: Forward and Reverse Diode Biasing
Generated from the validated SPICE netlist for this case.

🔒 This electrical diagram is premium. With the 7-day pass or the monthly membership you can unlock the complete didactic material and the print-ready PDF pack.🔓 See premium access plans

Measurements and tests

To validate the diode behavior, perform the following measurements using the multimeter.

1. Forward Bias Test (Anode to Positive)
* Voltage Measurement (VD): Set the multimeter to DC Volts. Place the red probe on the Anode (Node N1) and the black probe on the Cathode (Node 0).
* Result: You should read approximately 0.6 V to 0.7 V.
* Current Measurement (ID): Set the multimeter to DC mA. Break the circuit between R1 and D1, and insert the multimeter in series.
* Result: Using Ohm’s Law (I = (Vsource – VD) / R1), the current should be approximately 8.3 mA.

2. Reverse Bias Test (Cathode to Positive)
* Re-wiring: Disconnect D1, flip it 180 degrees, and reconnect it. Now the Cathode (stripe) connects to N1 and the Anode connects to 0.
* Voltage Measurement (VD): Measure across the diode again.
* Result: You should read a value very close to the source voltage (9 V), indicating the diode is acting as an open switch.
* Current Measurement (ID): Measure the current in the loop.
* Result: The reading should be 0 mA (or negligible leakage current in the nano-amp range).

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* Practical case: Forward and Reverse Diode Biasing
* Based on Wiring Guide: Forward Bias Configuration

* --- Power Supply ---
* V1: 9 V DC supply connected between VCC and GND (Node 0)
V1 VCC 0 DC 9

* --- Components ---
* R1: 1 kΩ resistor between VCC and Node N1
R1 VCC N1 1k

* D1: 1N4148 Diode
* Anode connected to N1, Cathode connected to GND (0)
D1 N1 0 D1N4148

* --- Models ---
* Standard 1N4148 Model
.model D1N4148 D (IS=2.682n N=1.836 RS=0.5664 BV=100 IBV=100p CJO=4p TT=11.54n)

* --- Analysis Directives ---
* ... (truncated in public view) ...

Copy this content into a .cir file and run with ngspice.

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* Practical case: Forward and Reverse Diode Biasing
* Based on Wiring Guide: Forward Bias Configuration

* --- Power Supply ---
* V1: 9 V DC supply connected between VCC and GND (Node 0)
V1 VCC 0 DC 9

* --- Components ---
* R1: 1 kΩ resistor between VCC and Node N1
R1 VCC N1 1k

* D1: 1N4148 Diode
* Anode connected to N1, Cathode connected to GND (0)
D1 N1 0 D1N4148

* --- Models ---
* Standard 1N4148 Model
.model D1N4148 D (IS=2.682n N=1.836 RS=0.5664 BV=100 IBV=100p CJO=4p TT=11.54n)

* --- Analysis Directives ---
* Operating Point analysis to see DC bias values
.op

* Transient analysis to log data (1ms duration)
.tran 10u 1m

* --- Output Directives ---
* Print supply voltage and diode forward voltage
.print tran V(VCC) V(N1)

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (108 rows)
Index   time            v(vcc)          v(n1)
0	0.000000e+00	9.000000e+00	7.143329e-01
1	1.000000e-07	9.000000e+00	7.143290e-01
2	2.000000e-07	9.000000e+00	7.143286e-01
3	4.000000e-07	9.000000e+00	7.143286e-01
4	8.000000e-07	9.000000e+00	7.143286e-01
5	1.600000e-06	9.000000e+00	7.143286e-01
6	3.200000e-06	9.000000e+00	7.143286e-01
7	6.400000e-06	9.000000e+00	7.143286e-01
8	1.280000e-05	9.000000e+00	7.143286e-01
9	2.280000e-05	9.000000e+00	7.143286e-01
10	3.280000e-05	9.000000e+00	7.143286e-01
11	4.280000e-05	9.000000e+00	7.143286e-01
12	5.280000e-05	9.000000e+00	7.143286e-01
13	6.280000e-05	9.000000e+00	7.143286e-01
14	7.280000e-05	9.000000e+00	7.143286e-01
15	8.280000e-05	9.000000e+00	7.143286e-01
16	9.280000e-05	9.000000e+00	7.143286e-01
17	1.028000e-04	9.000000e+00	7.143286e-01
18	1.128000e-04	9.000000e+00	7.143286e-01
19	1.228000e-04	9.000000e+00	7.143286e-01
20	1.328000e-04	9.000000e+00	7.143286e-01
21	1.428000e-04	9.000000e+00	7.143286e-01
22	1.528000e-04	9.000000e+00	7.143286e-01
23	1.628000e-04	9.000000e+00	7.143286e-01
... (84 more rows) ...

Common mistakes and how to avoid them

  • Measuring current in parallel: Never connect the multimeter across the diode while in «Current/Amps» mode. This creates a short circuit and may blow the multimeter’s fuse. Always measure current in series.
  • Omitting the resistor: Connecting a diode directly to a voltage source (above 0.7 V) without a resistor will cause unlimited current flow, instantly destroying the diode (and potentially the power supply).
  • Misidentifying terminals: The stripe on the diode body indicates the Cathode. In forward bias, the Cathode must point toward the lower potential (GND).

Troubleshooting

  • 0 V measured across D1 in Forward Bias: The diode might be shorted internally or the power supply is off. Check V1 voltage first.
  • 0 mA in Forward Bias: The circuit is open. Check if the breadboard connections are loose or if the resistor value is too high (e.g., 1 MΩ instead of 1 kΩ).
  • 9 V across R1 in Reverse Bias: The diode is conducting when it should not. Ensure D1 is actually reversed (stripe facing positive voltage) or check if D1 is damaged (shorted).
  • Diode gets hot: The current is too high. Ensure R1 is at least 330 Ω for a 9 V supply.

Possible improvements and extensions

  • Visual Indicator: Replace the standard silicon diode (D1) with an LED. The light will visually confirm when current is flowing (Forward Bias) and turn off when blocked (Reverse Bias).
  • I-V Curve Tracing: Use a variable power supply (0 V to 10 V) and record the current at 0.1 V steps to plot the characteristic exponential curve of the diode.

More Practical Cases on Prometeo.blog

Find this product and/or books on this topic on Amazon

Go to Amazon

As an Amazon Associate, I earn from qualifying purchases. If you buy through this link, you help keep this project running.

Quick Quiz

Question 1: What is the primary objective of this experiment?




Question 2: In a forward bias configuration, what is the expected voltage drop across a silicon diode?




Question 3: What happens to the current when the diode is in reverse bias?




Question 4: Which component functions as the Device Under Test (DUT) in this experiment?




Question 5: What is the purpose of the resistor in this circuit?




Question 6: Which of the following is a use case mentioned for diodes in the text?




Question 7: In reverse bias, what voltage value is expected across the diode?




Question 8: What specific logic family is mentioned as a use case for diodes?




Question 9: How does the diode assist in power supplies according to the text?




Question 10: What function does a diode perform in signal clipping?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

Follow me: