Practical case: Full-wave bridge rectifier

Full-wave bridge rectifier prototype (Maker Style)

Level: Medium – Analyze a Graetz bridge to convert AC to pulsating DC and measure total voltage drop.

Objective and use case

In this practical case, you will build a standard Graetz bridge circuit using four diodes and an AC voltage source to supply a resistive load. This circuit converts an alternating current input (where voltage polarity changes) into a pulsating direct current output (where voltage polarity remains positive).

Why it is useful:
* Power Supplies: It is the fundamental first stage in converting AC mains power to DC for charging laptops, phones, and powering appliances.
* Motor Control: Used in DC motor drives to run motors from an AC supply.
* Polarity Protection: Ensures that a device works correctly regardless of how the input power wires are connected.
* High Efficiency: Utilizes both the positive and negative half-cycles of the AC input, unlike a half-wave rectifier.

Expected outcome:
* Input Signal: A sinusoidal waveform (e.g., 12 V RMS / ~17 V Peak) at 60Hz.
* Output Signal: A series of positive «mounds» (pulsating DC) at 120Hz (double the input frequency).
* Voltage Drop: The peak output voltage will be approximately 1.4 V lower than the peak input voltage due to the forward voltage drop of two diodes in series (2 × 0.7 V).
* Current Flow: Current flows through the load resistor in the same direction during both AC half-cycles.

Target audience and level: Electronics students and hobbyists familiar with basic diode biasing.

Materials

  • V1: AC Voltage Source (Amplitude: 17 V [12Vrms], Frequency: 60Hz), function: Input supply
  • D1: 1N4007 Diode, function: Rectifier (Bridge arm 1)
  • D2: 1N4007 Diode, function: Rectifier (Bridge arm 2)
  • D3: 1N4007 Diode, function: Rectifier (Bridge arm 3)
  • D4: 1N4007 Diode, function: Rectifier (Bridge arm 4)
  • R1: 1 kΩ resistor, function: Output Load

Wiring guide

This guide uses specific node names to represent the connections. Ensure the AC source is floating relative to the DC ground to simulate the isolation provided by a transformer.

  • V1 (Positive terminal) connects to node AC1.
  • V1 (Negative terminal) connects to node AC2.
  • D1 (Anode) connects to node AC1.
  • D1 (Cathode) connects to node VOUT.
  • D2 (Anode) connects to node AC2.
  • D2 (Cathode) connects to node VOUT.
  • D3 (Anode) connects to node 0 (GND).
  • D3 (Cathode) connects to node AC1.
  • D4 (Anode) connects to node 0 (GND).
  • D4 (Cathode) connects to node AC2.
  • R1 connects between node VOUT and node 0 (GND).

Conceptual block diagram

Conceptual block diagram — LM7812 Full-Wave Bridge Rectifier
Quick read: inputs → main block → output (actuator or measurement). This summarizes the ASCII schematic below.

Schematic

[ INPUT SOURCE ]               [ PROCESSING / LOGIC ]               [ OUTPUT LOAD ]

[ AC Source V1 ]
(17 V Amp / 60Hz)
       |
       +----(Node AC1)----->+-----------------------------+
                            |    FULL-WAVE BRIDGE         |
                            |                             |
                            |  [ Diodes D1 & D2 ]         |
                            |  (Direct Positive Peaks)    |--(Node VOUT)--> [ Resistor R1 ]
                            |                             |                 (1 kOhm)
                            |                             |                     |
       +----(Node AC2)----->|  [ Diodes D3 & D4 ]         |                     |
       |                    |  (Direct Negative Peaks)    |                     v
       |                    |  (Create Return Path)       |                    GND
(Source Return)             |                             |
                            +-----------------------------+
                                          |
                                          v
                                     (Node 0/GND)
Schematic (ASCII)

Measurements and tests

Perform the following steps to validate the circuit operation using an oscilloscope or a multimeter:

  1. Input Verification: Connect channel 1 of the oscilloscope across AC1 and AC2. Verify a full sine wave with a frequency of 60Hz.
  2. Output Visualization: Connect channel 2 of the oscilloscope across R1 (Probe on VOUT, Clip on 0). Observe that the negative portions of the sine wave have been «flipped» up, creating a continuous chain of positive pulses.
  3. Frequency Measurement: Measure the frequency of the signal at VOUT. It should be exactly 120Hz (double the input frequency).
  4. Voltage Drop Analysis: Measure the peak voltage of the Input (Vpeakin) and the peak voltage of the Output (Vpeakout).
    • Vpeakout should be approximately Vpeakin – 1.4 V. This accounts for the 0.7 V drop across D1 and 0.7 V drop across D4 (during one cycle) or D2 and D3 (during the other).

SPICE netlist and simulation

Reference SPICE Netlist (ngspice) — excerptFull SPICE netlist (ngspice)

* Title: Practical case: Full-wave bridge rectifier

* --- Component Instantiation ---

* V1: AC Voltage Source (Amplitude: 17 V, Frequency: 60Hz)
* Wiring: V1 (Positive) -> AC1, V1 (Negative) -> AC2
* Note: Source is floating relative to ground (Node 0), connected only to the bridge.
V1 AC1 AC2 SIN(0 17 60)

* D1: 1N4007 Diode (Bridge arm 1)
* Wiring: Anode -> AC1, Cathode -> VOUT
D1 AC1 VOUT 1N4007

* D2: 1N4007 Diode (Bridge arm 2)
* Wiring: Anode -> AC2, Cathode -> VOUT
D2 AC2 VOUT 1N4007

* D3: 1N4007 Diode (Bridge arm 3)
* Wiring: Anode -> 0 (GND), Cathode -> AC1
D3 0 AC1 1N4007
* ... (truncated in public view) ...

Copy this content into a .cir file and run with ngspice.

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* Title: Practical case: Full-wave bridge rectifier

* --- Component Instantiation ---

* V1: AC Voltage Source (Amplitude: 17 V, Frequency: 60Hz)
* Wiring: V1 (Positive) -> AC1, V1 (Negative) -> AC2
* Note: Source is floating relative to ground (Node 0), connected only to the bridge.
V1 AC1 AC2 SIN(0 17 60)

* D1: 1N4007 Diode (Bridge arm 1)
* Wiring: Anode -> AC1, Cathode -> VOUT
D1 AC1 VOUT 1N4007

* D2: 1N4007 Diode (Bridge arm 2)
* Wiring: Anode -> AC2, Cathode -> VOUT
D2 AC2 VOUT 1N4007

* D3: 1N4007 Diode (Bridge arm 3)
* Wiring: Anode -> 0 (GND), Cathode -> AC1
D3 0 AC1 1N4007

* D4: 1N4007 Diode (Bridge arm 4)
* Wiring: Anode -> 0 (GND), Cathode -> AC2
D4 0 AC2 1N4007

* R1: 1 kΩ Resistor (Output Load)
* Wiring: VOUT -> 0 (GND)
R1 VOUT 0 1k

* --- Models ---
* Standard model for 1N4007 Rectifier Diode
.model 1N4007 D (IS=7.03n RS=0.034 N=1.81 BV=1000 IBV=0.5u CJO=10p TT=0.1u)

* --- Analysis Commands ---
* Transient analysis: 60Hz period is ~16.6ms.
* Simulating 50ms to capture approximately 3 full cycles.
.tran 50u 50m

* --- Output Directives ---
* Print voltages at AC inputs (relative to GND) and the rectified Output
.print tran V(AC1) V(AC2) V(VOUT)

* Calculate DC operating point
.op

.end

Simulation Results (Transient Analysis)

Simulation Results (Transient Analysis)
Show raw data table (1016 rows)
Index   time            v(ac1)          v(ac2)          v(vout)
0	0.000000e+00	3.036573e-18	3.036573e-18	-7.53268e-22
1	5.000000e-07	1.602212e-03	-1.60221e-03	-9.54567e-15
2	1.000000e-06	3.204481e-03	-3.20437e-03	1.126318e-07
3	2.000000e-06	6.409036e-03	-6.40866e-03	3.747988e-07
4	4.000000e-06	1.281816e-02	-1.28172e-02	9.375665e-07
5	8.000000e-06	2.563689e-02	-2.56338e-02	3.056599e-06
6	1.600000e-05	5.127600e-02	-5.12650e-02	1.103556e-05
7	3.200000e-05	1.025657e-01	-1.02513e-01	5.319168e-05
8	6.400000e-05	2.053399e-01	-2.04787e-01	5.532611e-04
9	1.140000e-04	3.725509e-01	-3.57833e-01	1.471794e-02
10	1.640000e-04	5.903791e-01	-4.60003e-01	1.303764e-01
11	2.140000e-04	8.628382e-01	-5.07168e-01	3.556700e-01
12	2.640000e-04	1.155738e+00	-5.33407e-01	6.223310e-01
13	3.140000e-04	1.456815e+00	-5.50867e-01	9.059481e-01
14	3.640000e-04	1.761378e+00	-5.64128e-01	1.197250e+00
15	4.140000e-04	2.068103e+00	-5.74401e-01	1.493702e+00
16	4.640000e-04	2.375673e+00	-5.82891e-01	1.792782e+00
17	5.140000e-04	2.683430e+00	-5.90142e-01	2.093289e+00
18	5.640000e-04	2.990978e+00	-5.96439e-01	2.394538e+00
19	6.140000e-04	3.297988e+00	-6.02000e-01	2.695989e+00
20	6.640000e-04	3.604206e+00	-6.06966e-01	2.997240e+00
21	7.140000e-04	3.909408e+00	-6.11453e-01	3.297955e+00
22	7.640000e-04	4.213406e+00	-6.15537e-01	3.597869e+00
23	8.140000e-04	4.516026e+00	-6.19284e-01	3.896742e+00
... (992 more rows) ...

Common mistakes and how to avoid them

  1. Ground Loops (Scope): Connecting the oscilloscope ground clip to AC1 or AC2 while the circuit is mains-referenced can cause a short circuit. Solution: Only connect the scope ground to the common circuit ground (0) at the load, or use a differential probe for the input.
  2. Diode Orientation: Inserting a diode backward in the bridge. Solution: Ensure that two diodes point towards the positive DC output node (VOUT) and two diodes point away from the ground node (0).
  3. Ignoring Power Ratings: Using a resistor with low wattage for R1. Solution: Calculate power P = V^2 / R. For 17 V peak, P ≈ 0.3W. Use a 0.5W resistor or greater.

Troubleshooting

  • Symptom: The output looks like a half-wave rectifier (gaps between pulses).
    • Cause: One of the diodes is open (disconnected or blown).
    • Fix: Check continuity of all four diodes; replace the faulty one.
  • Symptom: Zero output voltage.
    • Cause: Short circuit in the load or open circuit in the source/wiring.
    • Fix: Check connections at AC1 and AC2; ensure R1 is not shorted.
  • Symptom: Input fuse blows or source current is excessive.
    • Cause: One or more diodes are shorted, or a diode is installed in reverse (creating a direct path from AC to Ground).
    • Fix: Test diodes for shorts using the diode check mode on a multimeter.

Possible improvements and extensions

  1. Filtering: Add a capacitor (e.g., 470 µF) in parallel with R1 to fill in the gaps between pulses, creating a smooth DC voltage (Ripple reduction).
  2. Regulation: Connect a voltage regulator (like an LM7812 or a Zener diode circuit) after the filter capacitor to produce a constant, stable DC voltage regardless of input fluctuations.

More Practical Cases on Prometeo.blog

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Quick Quiz

Question 1: What is the primary function of a Graetz bridge circuit?




Question 2: How many diodes are typically used to build a standard Graetz bridge?




Question 3: Why is the Graetz bridge considered more efficient than a half-wave rectifier?




Question 4: If the input AC frequency is 60Hz, what is the frequency of the pulsating DC output in a Graetz bridge?




Question 5: What is the approximate total voltage drop expected at the peak output compared to the peak input?




Question 6: Why does the voltage drop occur in this circuit?




Question 7: Which component serves as the rectifying element in the described circuit?




Question 8: What happens to the direction of current flow through the load resistor during the negative half-cycle of the AC input?




Question 9: If the input source provides 12 V RMS, what is the approximate peak voltage amplitude mentioned in the text?




Question 10: Besides power supplies, what is another use case mentioned for the Graetz bridge?




Carlos Núñez Zorrilla
Carlos Núñez Zorrilla
Electronics & Computer Engineer

Telecommunications Electronics Engineer and Computer Engineer (official degrees in Spain).

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